lambda keyword creates an anonymous function at runtime. Anonymous function sometimes is more
convenient when used with itertools or enclosed in another function.
>>> f = lambda x: x%2 >>> f(3)
0The above code is equivalent to:
>>> def f(x): return x%2;
lambdawith itertools is very convenient:
>>> from itertools import * >>> data = [2,6,9,3,1,5] >>> x = filter(lambda x: x%2, data) >>> for i in x: print (i)
9 3 1 5